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Exercise S-1.3.2

Practice Exercise in Technical Mechanics 1, Rigid Body Statics.

Topic: Central Force Systems - Third Basic Task: Decomposition of a Force

Practice Exercise S-1.3.2

Central Force Systems - Third Basic Task: Decomposition of a Force

Problem Statement

A mass with the weight force FG is hanging on two ropes.

This illustration shows a weight force on two ropes. The ropes are attached to the ceiling.
Fig. 1: Weight force on two ropes

What are the components of the force FG = 10 kN in the direction of ropes 1 and 2?

Before You Embark on This Quest: A Pre-Mission Briefing

Before you dive into this adventure, let's do a quick check to see if you're ready for the challenge.

What's the Big Deal?
What topic are we dealing with here? Can you explain why?

All the lines of action of the attacking forces intersect at one point. So, we're dealing with a central force system.

Need a Little Refresher?

If you're not quite familiar with central force systems, no worries! Here are some refresher courses to get you up to speed:

Alright, You're Ready for the Task!

Good luck!

Graphical Solution

Okay, let's figure out the magnitudes of the components of the force FG in the direction of ropes 1 and 2. First, let's give them unique labels. A good choice would be FGS1 and FGS2.

Step 1: Check the layout diagram

Take a close look at the picture in the problem statement first. Then, read the problem statement carefully and create a layout diagram. This will give you an overview of everything important.

Use a Cartesian coordinate system as the basis for the diagram. The common point of attack of the forces is the origin (0,0) of the coordinate system.

The position of the force FG and the lines of action of the forces FGS1 and FGS2 are given. Draw them into the diagram first:

Layout Diagram
Fig. 2: Layout Diagram: Coordinate system with force FG

While you're at it, you can also enter the angles of the lines of action to the two coordinate axes, as shown in Fig. 2. They are obtained from the two measured angles, similar triangles, and the fact that the coordinate axes are arranged at a right angle to each other, i.e., at a 90° angle.

Now you can add the forces FGS1 and FGS2.

You have already drawn their lines of action. The question remains, in which direction they act.

The components of the force FG are required, so FGS1 and FGS2 must form a force parallelogram whose diagonal is FG.


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Analytical Solution

To solve this problem numerically, a sketch of the situation is very helpful.

First, we give unique labels to the components of the force FG in the direction of ropes 1 and 2. A good choice is FGS1 and FGS2.

Step 1: Create a sketch

Take a close look at the image in the problem statement. Read the problem statement carefully and create a sketch. This will give you a clear overview of everything important.

For the sketch, use a Cartesian coordinate system. The common point of application of the forces is the origin (0,0) of the coordinate system.

The position of the force FG and the lines of action of the forces FGS1 and FGS2 are given. Draw them into the diagram first:

Sketch
Fig. 2: Sketch: Coordinate system with force FG

While you're at it, you can also enter the angles of the lines of action to the two coordinate axes, as shown in Fig. 2. They are obtained from the two measured angles, similar triangles, and the fact that the coordinate axes are arranged at a right angle to each other, i.e., at a 90° angle.

Now you can add the forces FGS1 and FGS2.

Their lines of action have already been drawn in. The question remains in which direction they act.

We are looking for the components of force FG, so FGS1 and FGS2 must form a force parallelogram, whose diagonal is FG.


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  • Guaranteed premium membership for one week. Access starts on the day of activation and ends automatically at 0:00 CET (Central European Time) on the following week's day. No cancellation necessary.

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